One small and one large animal puzzle kit cost $16 altogether. If the large kit costs three times as much as the small kit, how much does each kit cost?
4 and 12
A= large animalpuzzle kit.
a= small animal puzzle kit.
A + a = 16
A = 3a
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solve for A and a.
Hint: Since A = 3a, just substitute 3a for the A in the first equation to have 3a + a 16. Then solve for a. With that value, place it into the other equation and solve for A. Post your work if you get stuck.
To solve the puzzle, we'll use the given information to set up two equations. Let's start by assigning variables:
Let A be the cost of the large animal puzzle kit.
Let a be the cost of the small animal puzzle kit.
According to the problem, the total cost of both kits is $16. Therefore, our first equation is:
A + a = 16
The problem also tells us that the large kit costs three times as much as the small kit. In other words, the cost of the large kit is three times the cost of the small kit, which can be written as:
A = 3a
Now that we have our two equations, we can solve for A and a.
1. Substitute 3a for A in the first equation:
3a + a = 16
2. Combine like terms:
4a = 16
3. Divide both sides by 4 to solve for a:
a = 4
Now that we have the value of a, let's substitute it back into the second equation to find A.
A = 3a
A = 3(4)
A = 12
So, the cost of the small animal puzzle kit (a) is $4, and the cost of the large animal puzzle kit (A) is $12.