Two flasks containing the same inert gas are at the same temperature and pressure of 800. mm Hg. One flask is injected into each of the flasks to allow phase equilibrium to be established. No leakage occurs. If the pressure in the 1.0 L flask is 900 mm Hg, what is the pressure in the 2.0 L flask?
Isn't phase equilibrium dependent on pressure of the vessel, not volume? If they are under the same equilibrium, the pressure has to be the same.
I may not be understanding what the situation is.
This question doesn't make sense.
Two flasks are at the same T and P "but then one is at 800 mmm Hg and the other 900 mm Hg." How can that be? Then, another, "one flask is injected into the other"---how can a flask be injected into another. Smart trick if you can do it.
I apologize for any confusion caused by the question. Let's try to clarify the situation and determine the pressure in the 2.0 L flask.
It seems that there might be some inconsistencies or incorrect information provided in the question. From the given information, it is not possible to determine the pressure in the 2.0 L flask. The principle of phase equilibrium, known as Dalton's law of partial pressures, states that in a mixture of gases, the total pressure is equal to the sum of the partial pressures of the individual gases. This principle assumes that the gases are in the same phase and under the same conditions of temperature and pressure.
However, in the given scenario, the two flasks containing the same inert gas are initially at the same temperature and pressure of 800 mm Hg. If both flasks are under the same equilibrium, the pressure should indeed be the same. It is unclear why the pressure in one of the flasks suddenly becomes 900 mm Hg. Furthermore, the statement about one flask being injected into the other is also puzzling, as it is not physically possible for a flask to be injected into another.
To solve this question, we would need a clear and consistent description of the scenario, indicating any changes that occurred or any additional relevant information.