write a balanced chemical equation for the reaction of aluminium selenide with water (to include physical states of reactants and products)to include brief decription of the strategy used and the sequence of partially balanced equations needed to reach final fully balaced equation .
http://www.webelements.com/webelements/compounds/text/H/H2Se1-7783075.html
To write a balanced chemical equation for the reaction between aluminium selenide (Al2Se3) and water (H2O), we need to follow a step-by-step process using partial equations.
Here's the strategy to balance the equation:
Step 1: Determine the formulas and states of the reactants and products.
The reactants are aluminium selenide (Al2Se3, solid) and water (H2O, liquid). The products are aluminium hydroxide (Al(OH)3, solid) and hydrogen selenide (H2Se, gaseous).
Step 2: Write the partial equations for the reactions of each element combining with the appropriate reactant.
a) Aluminium reacting with water:
2Al(s) + 6H2O(l) -> 2Al(OH)3(s) + 3H2(g)
b) Selenium reacting with water:
Se(s) + H2O(l) -> H2Se(g)
Step 3: Balance the partial equations to ensure the number of atoms on each side is equal.
a) Aluminium reaction:
2Al(s) + 6H2O(l) -> 2Al(OH)3(s) + 3H2(g)
b) Selenium reaction:
2Se(s) + 3H2O(l) -> 2H2Se(g) + 3O2(g)
Step 4: Combine the partial equations to form the final balanced equation.
2Al(s) + 6H2O(l) + 2Se(s) + 3H2O(l) -> 2Al(OH)3(s) + 3H2(g) + 2H2Se(g) + 3O2(g)
Simplifying and rearranging the equation, we have:
2Al(s) + 8H2O(l) + 2Se(s) -> 2Al(OH)3(s) + 3H2(g) + 2H2Se(g) + 3O2(g)
Note: The website you provided about hydrogen selenide (H2Se) does not include selenide reactions with water. However, by following the general principles of chemical reactions and using the balanced equation, we can deduce the reaction between aluminium selenide and water.