Posted by Shelley on Monday, January 29, 2007 at 1:23am.
Hello! I really don't think I am understanding my calc hw. Please help me fix my errors. Thank you!
1. integral from 0 to pi/4 of (tanx^2)(secx^4)dx
It says u = tan x to substitute
So if I use u = tan x, then my du = secx^2
then I have integral of (u^2)
then (1/3)u^3.....to get (1/3)tanx^3 then solve as 0 to pi/4 .......is that right?
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2. integral from 0 to 2root3 of (x^3)/(root(16-x^2))
I am pretty sure this has something to do with trig substitution. is it something with tan-1 or cos(theta)?
I am not sure how to go about this one at all.
Thanks again! =)
. integral from 0 to pi/4 of (tanx^2)(secx^4)dx
It says u = tan x to substitute
So if I use u = tan x, then my du = secx^2
no. du= sec^2x dx
then I have integral of (u^2)
Hmmm. INT u^2 sec^4x du/sec^2x
INT u^2 sec^2x du
how are you going to get rid of the sec^2 x?
second: draw the imaginary triangle, 4 is the hypotenuse, with angle theta , x is the opposite side, the adjacent side is sqrt (16-x^2)
then (1/3)u^3.....to get (1/3)tanx^3 then solve as 0 to pi/4 .......is that right?
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