a gas contains 51.7% sulfur & 51.6 percent oxygen. in a sample of gas, there is .620 g. v= 292 ml. p=806 torr. t= 378 K. what is the molecular formula.
how does the % sufur & oxygen tie into all this?
51.7% S and 51.6% O gives me more than 100.0%. OOps.
In order to determine the molecular formula of the gas, we need to use the information given: the mass of the gas (0.620 g), the volume (292 mL), the pressure (806 torr), and the temperature (378 K). However, there seems to be a mistake in the given information regarding the percentage composition of Sulfur (S) and Oxygen (O).
The sum of the percentages of each element in a compound should not exceed 100%. In this case, the total percentage is 51.7% + 51.6% = 103.3%, which is not possible. It seems to be an error or a typo. To solve this problem correctly, we need the correct percentage composition of Sulfur and Oxygen in the gas. Could you please provide the accurate percentages of Sulfur and Oxygen?