I need help simplifying radicals. The problem in priticular is the square root of 60x^2

√60x^2 can be simplified this way:

√(4 * 15 * x^2)

Can you see what to take out from under the square root sign?

√4 = 2 and √x^2 = x

Therefore, we end up with this:

2x√15

And that's as far as you can go to simplify this one!

I hope this will help.

To simplify the radical expression √(60x^2), we can begin by factoring the number inside the square root sign.

The number 60 can be factored as 4 * 15, and since x^2 is a perfect square, we can write the expression as √(4 * 15 * x^2).

Using the property of square roots that states √(ab) = √a * √b, we can separate the factors under the square root sign.

Thus, √(4 * 15 * x^2) can be written as √4 * √15 * √x^2.

√4 is equal to 2, and √x^2 simplifies to x. So, we have 2 * √15 * x.

Combining the like terms, we obtain the simplified radical expression: 2x√15.

Therefore, the simplified form of √(60x^2) is 2x√15.