Posted by **margie** on Sunday, January 28, 2007 at 11:41am.

5y^8-125

*you have to factor completley

easy. Take out the five:

5(y^8-25)

Now, isnt y^{8} the same as y^{4} )^{2} ? That is a square, so you have that y^{4} squared minus another perfect square? That factor as the difference of two squares. After doing that, you may have another difference of squares to factor.

So would it be 5(y^2-5)