Posted by **margie** on Sunday, January 28, 2007 at 11:41am.

5y^8-125

*you have to factor completley

easy. Take out the five:

5(y^8-25)

Now, isnt y

^{8} the same as y

^{4} )

^{2} ? That is a square, so you have that y

^{4} squared minus another perfect square? That factor as the difference of two squares. After doing that, you may have another difference of squares to factor.

So would it be 5(y^2-5)

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