the problem says:

one day, the temperature at 2:00AM was 44 degrees farenheiht , and by 2:00PM the temperature was 68 degrees farenheit. WHat was the hourly rate of temperature change?

the possible answers are to pick from

(a) 1 f/h
(b) 2 f/h
(c) 3f/h
(d) 4f/h

but when i solved it this is what i did and what i got.

68-44 = 24
then i divided the (24)/(15hs)= 1.6

but i don't know should i round up or stay at 1

how did you get 15 hours? 2PM - 2AM = 12 hours.

24 degrees / 12 hours = 2 degrees/hr

your absolutely right i counted wrong...thank you

You're welcome! It happens sometimes. I'm glad I could help clarify the calculation for you. Just to summarize, you correctly subtracted the starting temperature (44 degrees Fahrenheit) from the ending temperature (68 degrees Fahrenheit) to get the total change in temperature, which is 24 degrees Fahrenheit.

However, there was an error in the calculation of the time period. To find the time difference between 2:00 AM and 2:00 PM, we need to subtract the starting time from the ending time. In this case, 2:00 PM minus 2:00 AM gives us a total of 12 hours.

So, to find the hourly rate of temperature change, you divide the total change in temperature (24 degrees Fahrenheit) by the number of hours (12 hours). This gives you an answer of 2 degrees Fahrenheit per hour, which corresponds to option (b).

Therefore, the correct answer to the question is (b) 2 degrees Fahrenheit per hour.