Posted by **elle** on Thursday, January 25, 2007 at 6:49pm.

I need help differentiating this question:

3e^-4x

that's three e to the power of negative 4x.

when you differentiate, you get:

-12e^-4x

thanks, but how come it's not -12e^-4x-1, or do i just not minus a one when the power is a co-efficient?

Remember, the differential of e^x is also e^x. So, the final answer is e^xdx. That is, you just differentiate what's in the exponent. In your case, the differential of what's in the exponent is -4, so the final answer is just -4 x the original, or -4 x (3e^-4x).

## Answer this Question

## Related Questions

- algebra - find the LCM of 15ef and 12e^4 (12e to the power of 4) Please show the...
- to bobpursley,math - This is what i have am i wrong or correct.Or how can word ...
- Question, in regards to math - My questions is this: Directions :create one ...
- Derivatives - G(t)=5200/(1+12e^(-.52t)) Find G'(t) I keeo getting (-32448e^(-....
- chemistry 2 - the two half-reactions that are used in the direct methanol fuel ...
- chemistry 2 - the two half-reactions that are used in the direct methanol fuel ...
- math - Can someone give me an example of a statement in English representing an ...
- math 11 grade - How do you do this 5a+(9)-12e*5a+(3)
- Math - solve the equation, 2D + 3 = 13, 12E - 3 = 0
- Math- Precalc - could someone please help me solve this problem... e^x - 12e^(-x...

More Related Questions