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October 20, 2014

October 20, 2014

Posted by **elle** on Thursday, January 25, 2007 at 6:49pm.

3e^-4x

that's three e to the power of negative 4x.

when you differentiate, you get:

-12e^-4x

thanks, but how come it's not -12e^-4x-1, or do i just not minus a one when the power is a co-efficient?

Remember, the differential of e^x is also e^x. So, the final answer is e^xdx. That is, you just differentiate what's in the exponent. In your case, the differential of what's in the exponent is -4, so the final answer is just -4 x the original, or -4 x (3e^-4x).

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