# Belinda, Math

posted by
**Jasmine20** on
.

I aked the instructor about that problem that looked like this:

(w-(1)/(4))^2

and he said that what i thought was right. which was :

the answer:w^2-(1)/(2)w+(1)/(6)

Yes, that's right. I just thought your way of getting the answer was more complicated than it could have been.

With the placement of the parentheses in your answer I can't tell what you have, but I can tell you for sure that what Belinda wrote yesterday; i.e.,

[(w-1)/4]^{2} =

(w^{2} -2w +1)/16 is correct. That answer may be modified somewhat by certain arithmetic procedures but squaring w-1 MUST give, at least as a first step, w^{2} -2w +1.

see dr.bob222

then why did the instructor say that this was wrong about

w2 -2w +1

he said it had to be:

w squared and negative one half w plus one over sixteen.

**We aren't working the same problem. And the reason for that is that you didn't use parentheses correctly. You are working this problem. **

(w-(1)/(4))^2

** Written as you should have written it is
[w-(1/4)] ^{2}
**

*That give you*

w

w

^{2}- 0.5w + 1/16 which agrees with your previous answer and the teacher's answer.**I worked this one**

[(w-1)/4]

^{2}

**which gives the answer I posted yesterday.**

(w

^{2}-2w + 1)/16

*I hope this clears things up.*