Saturday
December 20, 2014

Homework Help: Physics/Science

Posted by TechnoBoi11 on Thursday, January 25, 2007 at 5:48am.

A startled armadillo leaps upward rising 0.547 m in the first 0.202 s.

(a) What is its initial speed as it leaves the ground?
_____m/s

(b) What is its speed at the height of 0.547 m?
_____m/s

(c) How much higher does it go?
_____m

Use distance vs time:
d=vi*t - 1/2 g t^2 solve for vi.

THen, for the second
d=vi*t -1/2 g t^2 solve for t, then
v=vi*t solve for v.

Finally, knowing vi, solve for the time to the top, where vf is zero.
Vf=vi*t -g t solve for t
height=vi*t - 1/2 g t^2 solve for height.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Physics - A startled armadillo leaps upward rising .536 m in teh first .197 s. ...
physics - A startled armadillo leaps upward, rising 0.521 m in the first 0.204 s...
physics - A startled armadillo leaps upward, rising 0.521 m in the first 0.204 s...
Physics - A startled armadillo leaps upward, rising 0.515 m in the first 0.203 s...
physics - A startled armadillo leaps upward, rising 0.596 m in the first 0.190 s...
introductory physics - A startled armadillo leaps upward rising 0.540 m in the ...
science - A startled armadillo leaps upward, rising .544 m in eh first .200s a) ...
physics - A startled armadill leaps upward rising .536 m in teh first .197 s. ...
last one i promise....physics - A startled armadill leaps upward rising .536 m ...
physics - Near the surface of the Earth, a startled armadillo leaps vertically ...

Search
Members