Sandy dropped a basketball from the top of her Mom'soffice building which is 72 meters tall. She discovered that the first bounce bounced 36m on the second bouce the ball bounced 18 meters. if this pattern continues, how high will the ball bounce on the sixth bounce?
72/(2^6)=??
im only in 7th grad i don't understand that
Looking at the problem tells you that 72 bounces back to 36 (1/2 of the original 72), the next bounce is 18 (again 1/2), the next bound will be 9, the next etc. Make a table like this.
#   height
0    72 meters
1    36 meters
2    18 meters
3    9 meters
4    4.5 meters
5    2.25 meters
6    1.125 meters.
But we can save a little time by simply raising 2n where n is the number of bounces. So 2n = 26 = 2*2*2*2*2*2 = 64
then 72/64 = 1.125
I hope this helps.
To find out how high the ball will bounce on the sixth bounce, we can use the formula:
height = initial height / (2 ^ n)
In this formula, "initial height" refers to the height the ball was dropped from (in this case, 72 meters), and "n" refers to the number of bounces.
So, to find the height of the sixth bounce, we substitute in the values:
height = 72 / (2 ^ 6)
Now, let's calculate this:
2 ^ 6 = 2 * 2 * 2 * 2 * 2 * 2 = 64
height = 72 / 64
height = 1.125 meters
Therefore, the ball will bounce to a height of 1.125 meters on the sixth bounce.