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October 22, 2014

October 22, 2014

Posted by **Jasmine20** on Wednesday, January 24, 2007 at 5:31pm.

Find the slope of any line perpendicular to the line through points(0,5) and (-3,-4).

THis is what i did.

m=(-4-5)/(-3-0)=(9)/(3)=3

y=mx+b

using points :(0,5)

5=3(0)+b

5=b

y=3x+5

so the slope of the perpendicular line is (-1)/(3)

When finding the slope, you got lucky. After (-4-5)/(-3-0) it is not 9/3, but -9/-3, which does equal 3. You got the slope right, but make sure you write it correctly.

The entire rest of the problem is correct.

Belinda,

so the perpendicular would be what i said of (-1)/(3).

and is it the same as : (3)/(-1).

The new slope is -1/3. But that isn't the same as 3/-1, that would be -3, which is different than -1/3

- geometry -
**kris**, Monday, October 1, 2007 at 3:09pmEquation of line parallel to 2x+3y=6 through (4,-3)

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