Directions:

Find the slope of any line perpendicular to the line through points(0,5) and (-3,-4).

THis is what i did.

m=(-4-5)/(-3-0)=(9)/(3)=3

y=mx+b

using points :(0,5)

5=3(0)+b
5=b

y=3x+5

so the slope of the perpendicular line is (-1)/(3)

When finding the slope, you got lucky. After (-4-5)/(-3-0) it is not 9/3, but -9/-3, which does equal 3. You got the slope right, but make sure you write it correctly.

The entire rest of the problem is correct.

Belinda,
so the perpendicular would be what i said of (-1)/(3).

and is it the same as : (3)/(-1).

The new slope is -1/3. But that isn't the same as 3/-1, that would be -3, which is different than -1/3

To find the slope of a line perpendicular to another line, you need to first find the slope of the given line. Let's call the slope of the given line "m".

Given points: (0, 5) and (-3, -4)

To find the slope "m" of the given line, you can use the formula: m = (y2 - y1) / (x2 - x1), where (x1, y1) and (x2, y2) are the coordinates of the two points on the line.

Using the formula, we can calculate the slope of the given line as follows:
m = (-4 - 5) / (-3 - 0)
= -9 / -3
= 3

So, the slope of the given line is 3.

Now, to find the slope of a line perpendicular to the given line, you can take the negative reciprocal of the slope. The negative reciprocal is the negative value of the reciprocal of the slope.

The reciprocal of 3 is 1/3. Taking the negative value of 1/3 gives -1/3.

So, the slope of any line perpendicular to the line passing through points (0, 5) and (-3, -4) is -1/3.

To summarize:
- The slope of the given line is 3.
- The slope of any line perpendicular to the given line is -1/3.

Equation of line parallel to 2x+3y=6 through (4,-3)