suppose that an isotope of uninhexium Uuh under goes a succession of seven a

-decay reactions what isotope would be the final product of these changes and show how u arrived at this answer and would the final product be a lanthanide,an actinide,atransition element or a typical element

Here is a web site that will let you see Uuh on the periodic table. I believe ti is element #116
www.webelements.com

I have answered this question twice in the last 3-4 days.
Remember an alpha particle is a He nucleus. That is 2He4.
So 7 alpha emissions would mean atomic number would be reduced by 7*2 = 14 and the mass number would be reduced by 7*4 = 28.

116Uuh292 ==>102X264 + 7 2He4. Note that the subscripts and superscripts must equal; i.e., the subscripts and superscripts on the left must equal to the sum of those on the right.
From the periodic table, find the element X. It will have an atomic number of 102. And its position in the periodic table will tell you if it is a lanthanide, actinide, etc. Post your thoughts if you need further assistance and explain in detail what you don't understand.

To determine the final product and its properties, we need to look at the reaction and use the information provided.

The starting isotope is uninhexium (Uuh), element number 116 with a mass number of 292 (116Uuh292).

The reaction involves seven alpha decay reactions, where an alpha particle is a helium nucleus, written as 42He4.

So, 116Uuh292 undergoes 7 alpha decay reactions, which means the atomic number will decrease by 7*2 = 14, and the mass number will decrease by 7*4 = 28.

Now, let's calculate the atomic number and mass number of the final product:

Atomic number of the final product = 116 - 14 = 102
Mass number of the final product = 292 - 28 = 264

So, the final product is an isotope with atomic number 102 and mass number 264 (102X264).

To determine whether the final product is a lanthanide, actinide, transition element, or a typical element, we need to refer to the periodic table.

You can use a website like www.webelements.com to find the element with atomic number 102. From the periodic table, you'll find that the element with atomic number 102 is Nobelium (No).

Nobelium (No) is an actinide element, which means the final product of the seven alpha decay reactions would also be an actinide element.

In summary, the final product of the seven alpha decay reactions from 116Uuh292 would be 102No264, an actinide element.