so in order to find out how many moles of O2 are produced from 12 moles of KClO3:

2 mols KClO3 form 3 mols O2
4 mols KClO3 form ? mols O2
Do you double the mols of O2
4 mols KClO3 form 6 mols O2?
6 mols KClO3 form 9 mols O2

To find out how many moles of O2 are produced from 12 moles of KClO3, you can use the given ratio of moles between KClO3 and O2.

According to the given information, 2 moles of KClO3 form 3 moles of O2.

To find out how many moles of O2 will be produced from 4 moles of KClO3, you can set up a proportion:

(2 moles KClO3 / 3 moles O2) = (4 moles KClO3 / x moles O2)

Simplifying the proportion, you can cross-multiply:

2 moles KClO3 * x moles O2 = 4 moles KClO3 * 3 moles O2

x moles O2 = (4 moles KClO3 * 3 moles O2) / 2 moles KClO3

x moles O2 = 6 moles O2

So, 4 moles of KClO3 will produce 6 moles of O2.

Similarly, you can find out how many moles of O2 will be produced from 6 moles of KClO3 by setting up another proportion:

(2 moles KClO3 / 3 moles O2) = (6 moles KClO3 / x moles O2)

Following the same steps as before, you'll find that 6 moles of KClO3 will produce 9 moles of O2.

Therefore, the final answer is that 6 moles of KClO3 will produce 9 moles of O2.