Posted by Chemwiz on .
RATES: If you double the concentration of reactant A in the reaction A + 2B ¨ C, what happens to the rate based on the rate law, rate = [A]2 [B]3? The rate would ___ by a factor of ___.
I can't read some of the signs; however, I THINK you probably wrote
A + 2B ==> C
then rate= k[A]^2[B]^3.
Doubling A will square that so rate would increase by 4.
Actually, as the coefficents determine the rate powers, the rate equation would actually be: