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AP Chem

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RATES: If you double the concentration of reactant A in the reaction A + 2B ¨ C, what happens to the rate based on the rate law, rate = [A]2 [B]3? The rate would ___ by a factor of ___.
increase, 2
increase, 4
decrease, 2
decrease, 4



I can't read some of the signs; however, I THINK you probably wrote
A + 2B ==> C

then rate= k[A]^2[B]^3.
Doubling A will square that so rate would increase by 4.

Actually, as the coefficents determine the rate powers, the rate equation would actually be:

rate=k[A]^1[B]^2

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