Sunday

April 19, 2015

April 19, 2015

Posted by **margie** on Tuesday, January 23, 2007 at 8:36pm.

*you have to factor by grouping,for more information just ask me*

First, take out 4x from the first two and y from the second:

4x(x+5) + y(x+5).

Then combine the 4x and the y:

(4x+y)(x+5).

That's your answer.

thanks. - can you help me with this one?

*48x^2y+20xz+12xy+5z

First, you should notice that 12*4=48 and 5*4 is 20. So, rearrange a little:

12xy + 48x^2y + 5z + 20xz.

Then, take out 12xy from the first two and 5z from the second two:

12xy(4x+1) + 5z(4x+1).j

Combine:

(12xy+5z)(4x+1).

thank you;please help me with my other problems...

math(one more time for today!)Please Help Belinda! - thanks,can you help me with...

math logic - A group of five students needs to break into two smaller groups in ...

please help me(math) - 4x^2+20x+5y+xy *you have top factor by grouping.If you ...

Algebra 1 - Are these right? xy - 3x - 8y + 24 (3x-y)-(8y+24) 8y+24 4x^2 + 20x...

Algebra - I am trying to factor polynomials by grouping the first two terms and ...

math,help - how can i factor this out completly x^4+x^3-12 i know that4*-3=-12 ...

algebra - this is what u do on your first problem....first u take out the ...

math,correction - Directions:Multiply Problem: ((x)/(3)+(3)/(4)) ((3x)/(4)-(3)/(...

math,help,factoring - i need help i don't know how to do the next step. factor ...

algebra 1 [fractions] - 8y^4+10y^3+12y+15 ----------------- 4y+5 divide then ...