OH! I get it now! Thanks so much for helping me out Count Iblis! (I told you I love this website!)

Factor the expression.

56x^3+43x^2+5x

I am used to the form of trinomial ax^2+bx+c, not ax^3+bx^2+cx. It is an even-numbered problem, so, of course, it was not on Hotmath. Any help is greatly appreciated! (I LOVE this website!)

56x^3+43x^2+5x =

x(56x^2 + 43x + 5)

Factor the quadratic expression in the brackets.

how do i factor
7n^5 + 7n^4 - 3n^2 -6n -3

U don't u wait for mr t to tell u how to Lol munkee

To factor the expression 7n^5 + 7n^4 - 3n^2 - 6n - 3, you can follow these steps:

1. Look for common factors: Start by checking if there is a common factor among all the terms. In this case, there is no common factor other than 1, so we move on to the next step.

2. Grouping terms: Group the terms together in pairs based on the potential common factors. We can pair the first two terms and the last three terms:

7n^5 + 7n^4 - 3n^2 - 6n - 3 = (7n^5 + 7n^4) + (-3n^2 - 6n - 3)

3. Factor out the common factor: Next, factor out the common factor from each pair of terms.

From the first pair:
7n^5 + 7n^4 = 7n^4(n + 1)

From the second pair:
-3n^2 - 6n - 3 = -3(n^2 + 2n + 1)

4. Simplify the expression: Now, you have factored out the common factors, so you can simplify the expression further by combining the simplified terms.

7n^5 + 7n^4 - 3n^2 - 6n - 3 = 7n^4(n + 1) - 3(n^2 + 2n + 1)

5. Check for further factorization: At this point, you have simplified the expression as much as possible. If you want to, you can check if there are any additional factors that can be factored out from the remaining terms, but in this case, there are no further factors.

Therefore, the factored form of the expression 7n^5 + 7n^4 - 3n^2 - 6n - 3 is:
7n^4(n + 1) - 3(n^2 + 2n + 1)