Thursday
September 18, 2014

Homework Help: chem+ help!

Posted by bon on Tuesday, January 23, 2007 at 1:55pm.

When 80.0 grams of a certain metal at 90.0 C was mixed with 100.0 grams of water at 30.0 C, the final equilibrium temperature of the mixture was 36.0 C. What is the specific heat (J/gC) of the metal?

I suppose I would use this formula:
q= mct
m= mass(g)
q= enthalpy change (j)
c= specifice heat capacity(J/gC)
t= temperature change(C)

not quite sure how to approach this question!?!?!?!

The sum of the heats added is zero (one is lost, so it is negative).

Heataddedwater + heataddedmetal=0
mw*cw*(Tf-Tiw) + mm*Cm*(Tf-Tim)=0

solve for Cm, the specific heat of the metal.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Chemistry - 100 grams of glucose is mixed with 500 grams of water. 10 grams of ...
Physics - One hundred twenty grams of metal at 88 degree Celsius is poured into ...
chemistry - if 50 grams of a substance with temperature of 20 degrees C and a ...
Physics - 120 grams of metal at 88 degree celcius is poured into a 70 grams ...
chemistry - a mixture of 100 grams of water is mixed with 100 grams of sodium ...
Physics - If you mix 100 grams of water at 20 degree centigrade with 100 grams ...
Chemistry - A 30.0 gram sample of water at 280. K is mixed with 50.0 grams of ...
chemistry - if 10 grams of metal A changes the temperature of 10 grams of water...
college Chemistry - 1. If 25 grams of Iron (III) hydroxide is dissolved in a ...
Chemistry - A coffee cup calorimeter contains 25.0 grams water at 23.8 C A 5.00g...

Search
Members