Posted by **Jasmine20** on Tuesday, January 23, 2007 at 1:24pm.

DIRECTIONS ARE.

WRITE THE EQUATION OF THE LINE L satisfying the given geometric conditions.

Problem is:

L has y-intercept (0,-3) and is parallel to the line with equation

y=(2/3)x +1.

So, this is what i did:

Y=(2/3)x+b....it passes through (0,-3)

-3=b

so, the equation is:

y=(2/3)x-3

then problem number 2:

L has y-intercept (0,2) and is perpendicular to the line with equation 2x-3y=6.

so this is whati did:

3x+2y=K..it passes through (0,2)

2(2)=k

4=k

so the equation would be:

3x+2y=4

first is correct.

second correct.

thank you for helping me out.

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