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November 22, 2014

November 22, 2014

Posted by **Jim (BIGEYE)** on Sunday, January 21, 2007 at 5:10am.

a) the time of acceleration

b) the linear speed of the rim of the flywheel

My answer for (a) is 104.7 secs, and for (b) is 10 m/s.

Appreciate if someone could check these answers if correct. If wrong, can they point me in the right direction.

TIA

Final angular speed = (angular acceleration) * time

400 rpm = 41.89 rad/s = (ang. acc.) * t

t = 104.7 s

final linear speed = R * (final angular speed) = [(0.48 m)/2]*41.89 rad/s = 10.05 m/s, but it is OK to show two significant figures, (10 m/s)

Thanks for that.

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