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February 27, 2015

February 27, 2015

Posted by **jasmine20** on Sunday, January 21, 2007 at 4:55am.

(y^5)^3(y^3)^2 divided by (y^4)^4

can someone show me how to solve these types of problems

(y^5)^3= y^15 multiply the powers

(y^3)^2=y^6 multiply the powers again as you have a power raised to a power

Then (y^15)*(y^6)=y^21 add powers now as you are multiplying expressions

(y^4)^4=y^16 multiply these powers

Finally (y^21)/(y^16) = y^5 subtract powers here as you are dividing expressions

thank you for explaining it to me.

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