Posted by Jan on .
Express the following in mol/kg
[H+]in a water with a pH of 6.8?
Ok, so the pH=-log10[H+]. Here we have a pH of 6.8 so we have...
solving we get...
converting from Liters to m^3 and dividing by the density of water we get...
Hope that helps!
I have a few more problems...can you help?
how about expressing 230 parts per thousand (ppt) of SO4^2- in mol
You are likely to have more luck if you repost as a new question.