Friday

October 31, 2014

October 31, 2014

Posted by **Jan** on Saturday, January 20, 2007 at 11:34pm.

[H+]in a water with a pH of 6.8?

Ok, so the pH=-log10[H+]. Here we have a pH of 6.8 so we have...

6.8=-10log10[H+]

solving we get...

[H+]=10^-6.8 mol/L

converting from Liters to m^3 and dividing by the density of water we get...

(10^-6.8 mol/L)*(L/0.001m^3)*(m^3/1000kg)=1.585(10^-7)mol/kg

Hope that helps!

Thanks.

I have a few more problems...can you help?

how about expressing 230 parts per thousand (ppt) of SO4^2- in mol

per kg?

You are likely to have more luck if you repost as a new question.

**Answer this Question**

**Related Questions**

Algebra 2 - If log10^9=0.95 and log10^2=0.30, find the following: 1. log10^9/2 2...

Math - How do I express these in scientific notation AND Log10 form? 1) ln(8.1) ...

Math - I can't calculate 1 as the answer given to the following problem. I keep ...

Chemistry - How many grams of water could have its temperature raised from 25 ºC...

Math - My question says: Find the exact alue of x for which (4^x)*(5^[4x+3])=(10...

Chemistry - Hi Dr. Bob, this is a chemistry question. I don't know how to go ...

Chemistry/lab math - I think I have these figured out correctly but I'm not sure...

AP Chemistry - The equilibrium constant for thermal dissociation of F2 F2(g)<...

Chemistry - Dr. Bob ok well here is what i have gotten so far: on the problem ...

Chemistry - Find the equilibrium moles for the following reaction with initially...