Posted by **mathstudent** on Friday, January 19, 2007 at 1:19pm.

Prove that if A is a diagonalizable matrix, then the rank of A is the number of nonzero eigenvalues of A.

http://ltcconline.net/greenl/courses/203/MatrixOnVectors/symmetricMatrices.htm
I've read the entire page and while it's on the correct topic, it doesn't prove what I'm looking to prove.

## Answer this Question

## Related Questions

- math - Prove that if A is a symmetric n x n matrix, then A has a set of n ...
- please help me(math) - 4x^2+20x+5y+xy *you have top factor by grouping.If you ...
- Math - How do you remember all the regruping stuff love Ally pethebridge First, ...
- Biology - Explain how the digestive, cardiovascular, and respiratory systems ...
- science - how many groups of birds are there and name them Since this is not my ...
- Science - Please help, I am so bored by my science lesson that I can barely ...
- math - The probability that a person has immunity to a particular disease is 0.3...
- spanish - What is the rule for formal commands? This site give information on ...
- (Life) - What is a good conflict resolution technique for employees? Talk ...
- Health - What are the requirements for the career of medical assistant? Do you ...