Sunday

October 26, 2014

October 26, 2014

Posted by **bailey** on Friday, January 19, 2007 at 9:31am.

F(x)=x^3-x^2-4x+4

Try to find the rational roots. If p/q is a root (p and q having no factors in common), then p must divide 4 and q must divide 1 (the coefficient of x^3).

The rational roots can thuis be +/1, +/2 and +/4. If you insert these values you find that the roots are at

x = 1, x = 2 and x = -2. This means that

x^3-x^2-4x+4 = A(x - 1)(x - 2)(x + 2)

A = 1, as you can see from equation the coefficient of x^3 on both sides.

Typo:

The rational roots can be

+/-1, +/-2 and +/-4

**Answer this Question**

**Related Questions**

algebra 2 - Factor completely with respect to the integers. 1. 9x^2 - 4 2. x^3...

Algebra - Can someone please explain how to do these problems. 1)write a ...

math - Still having problems solving this... 2x(2x + 1)^2 = 312 I started with: ...

Math - How to factor x^3 - 3x^2 + 4 =0 Use D'Alembert's Rational Roots Theorem. ...

math - Factor: x^3 - 3/4x - 1/4 The answer is: (x - 1)(x + 1/2)^2 How do I learn...

math - Still looking at how to solve these... Both are cubic polynomials? 43x^3...

algebra - using the rational root theorem to list all possible rational roots of...

algebra 1 [fractions] - 8y^4+10y^3+12y+15 ----------------- 4y+5 divide then ...

math - I HAVE THESE ANSWERS FOR THE PROBLEMS. COULD YOU DOUBLE CHECK PLEASE, ...

math - Could you please solve so I can double check my answers for the practice ...