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March 30, 2015

March 30, 2015

Posted by **claudia** on Thursday, January 18, 2007 at 10:28pm.

q = mass x specific heat x (Tf - Ti)

q is heat in Joules.

mass in grams

specific heat in J/g*C

Tf = final T

Ti = initial T

specific heat may be in other units, too,

Thanks for your response DrBob222, but i would like to know if to solve mass I only have to solve for "m" like in any algebra equation.

I was given this problem "1200 cal of heat energy is added to a liquid with a specific heat of 0.57cal/gC. If the temperature increases from 20C degree to 33C degree, what is the mass of the liquid?" can you explain how to set it up?

Yes, you solve it as you would any algebra problem. And since q is in calories and specific heat is in calories/g*C, we are ok with units.

1200 cal=q

m = ??

specific heat = 0.57 cal/g*c

Tf = 33

Ti=20

1200=m*0.57*(33-20)

solve for m (in grams)

Check my typing. Check my work.

Thanks I really appreciate your help, I have never gotten to this website before but is great. By the way I got 1192.59 for mass

Check my numbers and check my arithmetic BUT I don't get 1192.59.

I think you must have pushed a wrong button. I have

1200/(0.57*13) = 161.9 g

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**kelsie**, Wednesday, December 3, 2008 at 2:35amhow many grams of glucose are required to produce 50 mL of0.1 m solution?

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**zara**, Saturday, October 31, 2009 at 8:23amsorry am not here to help however i need help i dont know how to do the calorimetry conclusion can anyone help

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