solve this please....help me....12x(squared)+7x-10

Do you wish to factor this trinomial?

If so, the factors are:

(4x + 5)(3x - 2)

You can use the FOIL method to check.

If this is supposed to be an equation:

12x^2 + 7x - 10 = 0

...then set each factor equal to 0:

4x + 5 = 0
3x - 2 = 0

Solve each for x. You will have two possible solutions.

I hope this will help and is what you were asking.

x-(2y+3x)-2y

To solve the trinomial 12x^2 + 7x - 10, we can use the factoring method.

1. First, we need to break down the middle term (7x) into two numbers that when multiplied together give us the product of the first and last terms (12x^2 and -10).
- The factors of 12x^2 are 1x and 12x or 2x and 6x or 3x and 4x.
- The factors of -10 are 1 and -10 or -1 and 10 or 2 and -5 or -2 and 5.

2. We need to find the combination of factors that, when added, give us the coefficient of the middle term (7x).

The combination that works in this case is 2x and -5. So, we can rewrite the trinomial as:

12x^2 + 2x - 5x - 10

3. Now, we group the terms into pairs and factor out the greatest common factor (GCF) from each pair:

(12x^2 + 2x) - (5x + 10)
2x(6x + 1) - 5(6x + 1)

4. We can see that we now have a common binomial factor of (6x + 1). We can factor it out:

(2x - 5)(6x + 1)

So, the factored form of the trinomial is (2x - 5)(6x + 1).

If you meant to solve the equation 12x^2 + 7x - 10 = 0, the next step would be to set each factor equal to zero and solve for x:

2x - 5 = 0 or 6x + 1 = 0

Solving these equations will give you the possible solutions for x.