Monday

October 20, 2014

October 20, 2014

Posted by **Linds** on Thursday, January 18, 2007 at 8:41pm.

1/square root of x = x^(-1/2)

The derivative is -1/2 x^(-3/2)

can you keep going on the problem to not have negative exponents?

You can also use that the derivative of

1/f(x) is given by:

-f'(x)/[f(x)]^2

If you take f(x) = sqrt(x) and use that f'(x) = 1/[2*sqrt(x)], you find that the derivative is given by:

-1/2 * 1/[sqrt(x)]^3

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