Posted by **Linds** on Thursday, January 18, 2007 at 8:41pm.

find derivitive of 1/square root of x

1/square root of x = x^(-1/2)

The derivative is -1/2 x^(-3/2)

can you keep going on the problem to not have negative exponents?

You can also use that the derivative of

1/f(x) is given by:

-f'(x)/[f(x)]^2

If you take f(x) = sqrt(x) and use that f'(x) = 1/[2*sqrt(x)], you find that the derivative is given by:

-1/2 * 1/[sqrt(x)]^3

## Answer This Question

## Related Questions

- Calculus - Any help would be much appreciated with the steps involved in each ...
- Calculus - Any help would be much appreciated with the steps involved in each ...
- Chain Rule - Any help would be much appreciated with the steps involved in each ...
- calculus - 6. What is the derivative of y = square root of 3x ? a.dy/dx = square...
- Calculus - A rectangle is bounded by the x axis and the semicircle = square root...
- Algebra - Use the quadratic formula to solve the equation. Give exact answers: ...
- Algebra - Rationalize each expression by building perfect nth root factors for ...
- Calculus/Logarithms - Find the derivative of f(x) = (square root of x)(ln x). ...
- Math Help! - Four students worked to find an estimate for square root 22. Who is...
- Math - Four students work to find an estimate for square root 27. Who is closest...

More Related Questions