# Calculus

posted by
**Linds** on
.

find derivitive of 1/square root of x

1/square root of x = x^(-1/2)

The derivative is -1/2 x^(-3/2)

can you keep going on the problem to not have negative exponents?

You can also use that the derivative of

1/f(x) is given by:

-f'(x)/[f(x)]^2

If you take f(x) = sqrt(x) and use that f'(x) = 1/[2*sqrt(x)], you find that the derivative is given by:

-1/2 * 1/[sqrt(x)]^3