Posted by **Shay** on Thursday, January 18, 2007 at 5:27pm.

Determine the value(s) of k for which

x^2+(k-2)x-2k=0

has equal and real roots.

a x^2 + bx + c = 0 has two different roots if the discriminant D defined as:

D = b^2 - 4 a c does not equal zero.

If D = 0 then there is one root. That root is then real if b/a is real. In this case this means that:

(k-2)^2 + 8k = 0 --->

(k+2)^2 = 0 --->

k = -2

k must also be real and -2 is real, so k = -2 is a valid solution.

- algebra -
**Anonymous**, Thursday, October 4, 2007 at 9:05pm
its -3

## Answer This Question

## Related Questions

- maths2 - Use the discriminant to determine the number of real roots the equation...
- mathematics - Use the discriminant to determine the number of real roots the ...
- can someone please help me? - simplify the following expressions involving ...
- algebra - if a quadratic equation with real coefficents has a discriminant of 10...
- College Algebra--Still Confused - I have a few problems I need help with and ...
- College Algebra - I have a few problems I need help with and also do have ...
- math - I HAVE THESE ANSWERS FOR THE PROBLEMS. COULD YOU DOUBLE CHECK PLEASE, ...
- math - Could you please solve so I can double check my answers for the practice ...
- Math - Determine for what value(s) of d the quadratic equation 5x^2-10x+d = 0 ...
- calc - by applying rolle's theorem, check whether it is possible that the ...

More Related Questions