Posted by Shay on Thursday, January 18, 2007 at 5:27pm.
Determine the value(s) of k for which
x^2+(k2)x2k=0
has equal and real roots.
a x^2 + bx + c = 0 has two different roots if the discriminant D defined as:
D = b^2  4 a c does not equal zero.
If D = 0 then there is one root. That root is then real if b/a is real. In this case this means that:
(k2)^2 + 8k = 0 >
(k+2)^2 = 0 >
k = 2
k must also be real and 2 is real, so k = 2 is a valid solution.

algebra  Anonymous, Thursday, October 4, 2007 at 9:05pm
its 3
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