# algebra

posted by
**bailey** on
.

Divide (3x^3-x^2+8x-9) by (x-1)

Please help!

I'll show you how this works out:

3x^2 + 2x + 10

x - 1 | 3x^3 - x^2 + 8x - 9

3x^3 - 3x^2

2x^2 + 8x

2x^2 - 2x

10x - 9

10x - 10

1

Remember when you subtract, you change the signs. This did not divide evenly, so you will have a remainder of 1.

I hope this helps.