Posted by **Shay** on Wednesday, January 17, 2007 at 7:45pm.

find the x-intercepts of

y=3x^2-6x by factoring

y = 3x^2 - 6x

Factor out 3x:

y = 3x(x - 2)

Set each factor equal to 0:

3x = 0; x = 0

x - 2 = 0; x = 2

Those are your x-intercepts.

I hope this will help.

## Answer This Question

## Related Questions

- algebra - 3ax^2 - 27a You can factor that into 3a (x^2 - 9), which also equals ...
- Algebra: factoring - I need to find the value of x. 9x^3 + 9x = 30x^2 It's ...
- Math - find the x-intercepts by factoring g(x)=x^4-27x I'm really confused. All ...
- Calc - Profit=p(-p^2+33p+9)-9(-p^2+33p+9)+100 How do I simplify this so I can ...
- math?? factoring - 100N/m d^2 - 57.3d= 0 sigh...I can't figure out how to find d...
- FACTORING - I can't figure out how to factor this. I know you use the technique ...
- math - The rectangle given has a perimeter of 14 units. Find the value(s) of x ...
- Math Repost!!Please Help!!!! - 6-y --------- y^2-27-24 well it should simplify ...
- Greatest Common factors - I dont know these answers. Can you help me? Greatest ...
- MATH - HOW DO I SOLVE A QUADRATIC EQUATION BY FACTORING? Do you have a specific ...

More Related Questions