# precal

posted by
**eragon**
.

The smaller of 2 numbers is 10 less than 4 times the greater number. The bigger number is 19 more than the smaller one.

If x is the smaller number one equation is:

a)x+y=19

b)x=19-y

c)y=x+19

d)x=y+19

I'm almost positive it is d I just want to check.

A second equation is:

a)x=4y-10

b)x=4y+10

c)x=10-4y

d)x=(10-4)y

Again I'm pretty sure the answer is c, but want to make sure.

If x is the smaller number and y is the bigger number, and y is 19 more than x, how can x be y + 19? Think again.

x is 10 less than 4y. They tell you that. So how can (c) be consistent with that? It can't. Try again.