Posted by **chrissy** on Tuesday, January 16, 2007 at 3:52pm.

You can add or subtract complex numbers by treating the i as a variable and combining like terms.

I am having a lot of trouble figuring out these equations with imaginary numbers.

1. (3+2i)+(7-i)=

2.(1-6i)+(2-i)=

3. (2+i)-(3+i)=

4.(4+i)-(2-i)=

Can someone please walk me through how to do these problems? Thanks.

(3+2i)+(7-i)=

3 + 2i + 7-i=

3 + 7 + 2i - i =

10 + i

## Answer This Question

## Related Questions

- Algebra 2 - When dealing with imaginary and complex numbers, are there 2 ...
- Algebra - The function 5x^2+2x-1's domain is all real numbers, according to the ...
- algebra ll-imaginary numbers - where can i find help online about imaginary ...
- math - solve and simplify the answer completely by using pure imaginary numbers/...
- algebra - question The square root of a negative number is imaginary. That is ...
- Math - Factor the polynomial as the product of factors that are irreducible over...
- math - The discriminant of a quadratic equation is 35. The roots are: a) unequal...
- Math - i^6 = (i^2)^3 = (-1)^3 = -1 The square, not the square root of -1 is 1...
- Math - Find the real and imaginary parts of the following complex numbers: (i) 1...
- Math - Hi, I have to write a research paper and I decided to write about the ...

More Related Questions