# chemistry

posted by
**Noreen** on
.

how would i calculate; a 50g sample of water at 100 degrees is poured into a 50g sample of water at 25 degrees. with a specific heat of water (l) being 4.184 j/g degrees C.what will be the final temperature of the water?

heat gained + heat lost = 0

[massH2O*specificheat*(Tf-Ti)+[massH2O*specific heat*(Tf-Ti)].

Tf is final T. Solve for this.

Ti is initial T of each.

Post your work if you get stuck and need further assistance. There is a short cut way of doing this but the above equations works for almost anything.