what is the equation of the line with {3,3} and is perpendicular to the line y= negative 2x plus 3

The slope of the line is -2. The slope of a line perpendicular to this one must be its negative reciprocal, or 1/2.

Use the point-slope form to find the other line:

y - y1 = m(x - x1) -->point-slope form

y - 3 = 1/2(x - 3)

Can you take it from here to finish?

I hope this will help.

To finish solving the problem, you can simplify the equation using the distributive property:

y - 3 = 1/2 * x - 1.5

Next, you can rearrange the equation to isolate y:

y = 1/2 * x - 1.5 + 3

Simplifying further:

y = 1/2 * x + 1.5

So, the equation of the line that is perpendicular to y = -2x + 3 and passes through the point (3, 3) is y = 1/2 * x + 1.5.