what is the equation of the line with {3,3} and is perpendicular to the line y= negative 2x plus 3
The slope of the line is -2. The slope of a line perpendicular to this one must be its negative reciprocal, or 1/2.
Use the point-slope form to find the other line:
y - y1 = m(x - x1) -->point-slope form
y - 3 = 1/2(x - 3)
Can you take it from here to finish?
I hope this will help.
To finish solving the problem, you can simplify the equation using the distributive property:
y - 3 = 1/2 * x - 1.5
Next, you can rearrange the equation to isolate y:
y = 1/2 * x - 1.5 + 3
Simplifying further:
y = 1/2 * x + 1.5
So, the equation of the line that is perpendicular to y = -2x + 3 and passes through the point (3, 3) is y = 1/2 * x + 1.5.