Monday

March 30, 2015

March 30, 2015

Posted by **Lane** on Thursday, January 11, 2007 at 2:30pm.

an example problem is 4n^2-5n-6

can someone show me step by step how to factor these kind of problems easily?

Take the coefficient of your quadratic term in this case 4 and multiply it by your constant term in this case -6. You get -24. Then you want to figure out two numbers which when multiplied together give you -24 and when added together give you the value of the coefficient of your linear term in this case -5.

So, the two numbers are -8 and 3.

Take those two numbers and rewrite your problem changing you linear term in this case -5n using -8 and 3.

Changed problem is: 4n^2-8n+3n-6

Now factor by grouping. The first two terms can be factored into 4n(n-2) and the last two terms can be factored into 3(n-2). Notice you have the same factor in parentheses.

So, the original problem (4n^2-5n-6)can be factored into (4n+3)(n-2).

**Answer this Question**

**Related Questions**

Math (Algebra 2) - Factoring by Using a Quadratic Form Problem: x^4 + 8x^2 - 20 ...

Algebra - Can someone please help me with math problem and explain to me step by...

algebra - Can someone please show me how to solve this problem step by step ...

Algebra: factoring - I need to find the value of x. 9x^3 + 9x = 30x^2 It's ...

Algebra - 4x^4-18x^2=0. I have to find out what x equals by factoring. What I ...

Algebra 2 - I need to know how to solve quadratic equations by factoring. Can ...

math,factoring,help - Can someone please show me step by step how to do these. I...

Factoring - x2(squared)-4x+4 I would factor this into (X - 2)(X - 2) If you don'...

Math(factoring) - I need help with factoring trinomials completely. My teacher's...

algebra2 - Can you explain how to factor the following trinomials forms: x2 + bx...