A saturated solution of potassium chlorate is formed from 100 grams of water. if the saturated solution is cooled from 80 degrees celsius to 50 degrees celsius, how many grams of precipate are formed?

Do you have a table that lists the solubility at 80 and 50 degrees C?

30grams of KCL

Why did the saturated solution go to therapy? Because it had some serious solubility issues!

Unfortunately, I don't have a table on hand, but I can tell you that the solubility of potassium chlorate generally decreases as temperature decreases. So, when the solution is cooled from 80 degrees Celsius to 50 degrees Celsius, some of the dissolved potassium chlorate will likely precipitate out.

To determine the exact amount of precipitate formed, we need to know the solubility of potassium chlorate at those specific temperatures. If you can provide that information, I'd be happy to calculate it for you!

Unfortunately, I don't possess real-time data tables. However, I can explain how you can determine the solubility of potassium chlorate at different temperatures and calculate the mass of precipitate formed.

To find the solubility of potassium chlorate at 80 degrees Celsius and 50 degrees Celsius, you can consult a solubility chart or reference book specifically for potassium chlorate. Typically, solubility charts provide the maximum amount of solute that can dissolve per 100 grams of solvent at different temperatures.

Once you have determined the solubility at 80 degrees Celsius and 50 degrees Celsius, you can calculate the amount of dissolved potassium chlorate in the saturated solution at each temperature.

Assuming the solubility of potassium chlorate at 80 degrees Celsius is X grams per 100 grams of water, you can calculate the amount of dissolved potassium chlorate in the saturated solution by using the following formula:

Mass of dissolved potassium chlorate at 80 degrees Celsius = X g/100 g × 100 g

Similarly, assuming the solubility of potassium chlorate at 50 degrees Celsius is Y grams per 100 grams of water, you can calculate the amount of dissolved potassium chlorate at this temperature using the same formula:

Mass of dissolved potassium chlorate at 50 degrees Celsius = Y g/100 g × 100 g

To calculate the mass of precipitate formed when the saturated solution is cooled from 80 degrees Celsius to 50 degrees Celsius, you subtract the mass of dissolved potassium chlorate at 50 degrees Celsius from the mass of dissolved potassium chlorate at 80 degrees Celsius:

Mass of precipitate formed = Mass of dissolved potassium chlorate at 80 degrees Celsius - Mass of dissolved potassium chlorate at 50 degrees Celsius

Please note that to obtain the accurate solubility values and ensure the accuracy of the calculations, it is always best to refer to reliable sources such as scientific literature, textbooks, or solubility charts prepared specifically for potassium chlorate.

im sorry idk.

Subtract 50 from 80, then subtract that from 100