Posted by **TIFFANY** on Wednesday, January 10, 2007 at 10:26pm.

if 37.9 liters of NO at .993atm and 146 degrees celcius are decomposed by the reaction 2NO-->N2+O2

how many grams of nitrogen will be formed...

could you show mw step bu step how to do this ? thanks....i have finals tommorrow.... i need HHHHHHEEEEEEELLLLLLPPPPPPPP

PV=nRT

P=0.993 atm

V = 37.9 L

n = solve for this

R = 0.080206 L*atm/mol*K

T = 273 + 146 = 419 Kelvin

n = 1.095 mols ofNO.

mols N2 formed from the reaction =

mols NO x (1 mol N2/2 mols NO)=

1.095 x 1/2 = 0.547

grams N2 = mols x molar mass which I will leave for you to do.

grams N2 = 0.547 x 28 = ??

Check my thinking. Check my arithmetic.