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November 29, 2014

November 29, 2014

Posted by **Denise** on Wednesday, January 10, 2007 at 12:18am.

3 ln y= 1/2ln (2x+1) - 1/3ln (x+4) + ln C

ln y = (1/6)ln (2x+1) -(1/9)ln (x+4) + (1/3) ln C

y = e^ln y = e^[(1/6)ln (2x+1) -(1/9)ln (x+4) + (1/3) ln C]

= C^(1/3)* (2x+1)^(1/6) /(x+4)^(1/9)

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