belinda if ur still here to help i would appreciate it so much but 5z-2 (5z-2 is under a radical sign) +7=10

anyone else who knows how to solve this with it coming out equal please help thanks again :)

wow, I am SO incredibly stupid 3 times in a row! When you get to 5z=11, you divide 5 by each side and get z=11/5. When you plug it in, 5(11/5)=11, then -2=9. The sqrt of 9 is 3 and 3+7=10. Wow.

Is it (sqrt 5z-2)+7=10
If so, then
sqrt(5z-2)=3. Square both sides.
5z-2=9
5z=9+2=11
z=11/5
Check me out on that.

thanks belinda and no your not incredibly stupid i did the same thing, unless i am incredibly stupid lol

it still doesnt come up even???wierdi plugged it in and the square root of 5(1.2)-2 plus the 7 does not equal 10?
it come up to only 9 ? im confused :(

OK. 11/5 is not 1.2! 11/5 is 2.2. sqrt(5(2.2)-2)+7=10.

To solve the equation sqrt(5z-2) + 7 = 10, follow these steps:

Step 1: Subtract 7 from both sides of the equation to isolate the square root term on the left side:
sqrt(5z-2) = 10 - 7
sqrt(5z-2) = 3

Step 2: Square both sides of the equation to eliminate the square root:
(5z-2) = 3^2
5z-2 = 9

Step 3: Add 2 to both sides of the equation to isolate the variable term:
5z = 9 + 2
5z = 11

Step 4: Divide both sides of the equation by 5 to solve for z:
z = 11/5

Hence, the value of z that makes the equation true is z = 11/5 or 2.2.

However, when plugging in the value of z = 11/5 (or 2.2) into the original equation sqrt(5z-2) + 7 = 10, it seems to not equal to 10. Let's verify it:

sqrt(5(2.2) - 2) + 7 = sqrt(11 - 2) + 7 = sqrt(9) + 7 = 3 + 7 = 10

Therefore, after reevaluating the plugging in of the value, it does indeed correctly evaluate to 10. Sorry for any confusion that may have caused earlier.