# math correction

posted by
**Jasmine20** on
.

can someone correct this for me.

Business and finance. The cost for a long-distance telephone call is $0.36 for the first minute and $0.21 for each additional minute or portion thereof. Write an inequality representing the number of minutes a person could talk without exceeding $3.

Let x = be the number of minutes:

The first minute cost $0.36

The remaining x –1 minutes cost $0.21 each

So the remaining x- 1 minutes altogether costs $0.21 (x – 1)

Total cost = $0.36 + $0.21 (x – 1)

This must be less than or equal $3.00. So we have:

$0.36 +$0.21 (x- 1) <= $ 3.00

Multiply through by 100 and drop the $’s

36 + 21(x –1)<= 300

12 + 7 (x –1)<= 100 (In this step in order to get this equation I had to divide both sides by 3 to make the numbers smaller.)

12 + 7x – 7 <= 100

7x + 5 <=100