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November 26, 2014

November 26, 2014

Posted by **Scotty** on Sunday, January 7, 2007 at 11:43pm.

Hint: At three earth radii from the surface of the Earth, the gravity force (weight) of the spacecraft will be reduced to

(1/4)^2 = 1/16 of the weight when the spacecraft is at the Earth's surface, since it is 4 times farther from the Earth's center.

(1/16) x M g = ?

g is the value at the Earth's surface, 9.8 m/s^2. M = 1600 kg.

- Physics -
**Anonymous**, Wednesday, December 17, 2008 at 6:57pm9040

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