Sunday
May 19, 2013

# Homework Help: Math

Posted by Chris on Sunday, January 7, 2007 at 7:58pm.

How do I solve this?
tan^2x= 2tanxsinx

My work so far:
tan^2x - 2tanxsinx=0
tanx(tanx - 2sinx)=0

Then the solutions are:

TanX=0

and
sinX/cosX = 2 sin X

Divide thru by sinX: we have to check this later to see if allowed (ie sinX is not zero)
cosX=1/2
Now, if CosX=1/2, then sinX must equal sqrt3/2, from cos^2 + sin^2=1 for any angle.

So, solutions: x = arctan 0
and x=arccos 1/2

check that.

No one has answered this question yet.

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