posted by DrBob222 on .
What I wrote is the balanced ionic equation. The ++ are written as exponents and could be written as we usually do it as
Cu^+2 + Zn ==> Zn^+2 + Cu. For the molecular equation, it is
Cu(NO3)2 + Zn ==> Zn(NO3)2 + Cu
So the ionic equation for adding copper(II)nitrate to pure zinc is:
then would the balanced equation be:
No. Didn't I write the balanced equation for you yesterday. What is with the ^2N? I know the caret means exponent but what is N?
Cu++ + Zn ==>Zn++ + Cu
I thought I was supposed to add nitrogen to both sides of the equation to balanec it. So is Cu++Zn--->Zn++Cu
the balanced equation for copper(II)nitrate plus pure zinc?