# Chemistry Equation(again)

posted by
**DrBob222** on
.

What I wrote is the balanced ionic equation. The ++ are written as exponents and could be written as we usually do it as

Cu^+2 + Zn ==> Zn^+2 + Cu. For the molecular equation, it is

Cu(NO3)2 + Zn ==> Zn(NO3)2 + Cu

So the ionic equation for adding copper(II)nitrate to pure zinc is:

Cu^2N+Zn---> Zn^2+Cu

then would the balanced equation be:

Cu^2N+Zn---> Zn^2CuN

No. Didn't I write the balanced equation for you yesterday. What is with the ^2N? I know the caret means exponent but what is N?

Cu^{++} + Zn ==>Zn^{++} + Cu

I thought I was supposed to add nitrogen to both sides of the equation to balanec it. So is Cu++Zn--->Zn++Cu

the balanced equation for copper(II)nitrate plus pure zinc?