Posted by **Chris** on Saturday, January 6, 2007 at 8:29pm.

One atmospheric pressure is that which will support a column of mercury 760.0 mm high. Show that 1 atm equals 1.013 x 10^5 N/m^2. Take the density of Hg to be 13.60 g/cm^3 and the gravitational constant to be 9.80 m/s^2. (You may find unit analysis helpful!)

I have no idea where to begin. Any help would be appreciated.

Start with figuring the weight of a column of mercury ( cross sectional area A), then the pressure (weight/A). Weight= mass*g=density*volumecolumn*g=denstiy*A*h*g

## Answer This Question

## Related Questions

- math - The average air pressure at sea-level will support the column of mercury ...
- H. CHemistry - if the atmosphere can support a column of mercury 760 mm high at ...
- chemistry - If a cetain pressure supports a 256 mm high column of mercury, how ...
- chemistry - what pressure (in atm) is exerted by a column of mercury 1.4O high? ...
- chemistry - If the atmosphere can support a column of mercury 760 mm high at ...
- Chemistry - One atmosphere of pressure will push a column of mercury to a ...
- Chemistry - A column of mercury in a barometer is 767.3 mm Hg high. Note, that ...
- Physics - Mercury has a density of 13600 kg/m3. At what depth in millimetres is...
- Physics - Mercury has a density of 13600 kg/m3. At what depth in millimetres is...
- chem-Bob - What pressure (atm) is exerted by a column of ethanol 65.0 cm high? ...

More Related Questions