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March 3, 2015

March 3, 2015

Posted by **Katrina** on Friday, January 5, 2007 at 11:51pm.

i dont knw how to do this kind of problems..can anyone teach me???

Forget about the fact that there are 52 cards in a deck. The number 52 will not figure in the answer. What matters is that there are four suits to draw from for each number, J, K, K or Ace. The number of combinations of three aces out of four cards is

4!/(3!*1!) = 4

The number of ways of drawing two kings out of four cards is 4!/(2!*2!) = 24/4 = 6

The answer is the product of the number of three-ace combinations and the number of two-king combinations. That number is 24.

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