Posted by **becky** on Thursday, January 4, 2007 at 9:41pm.

the vertices are at (2,1) and (2,7) and focus is at (2,*)

write the equation of the hyperbola that meets each set of conditions.

Is the asterisk supposed to be an 8? It has to be some number. I will set this up for you later of you respond. The fomulas you need are in most calculus and analytic geometry texts.

yeah it is an 8

your vertices are (2,1) and (2,7), so your centre is (2,4), the midpoint.

Since your hyperbola is vertical it must have equation:

(x-2)^2 over a^2 - (y-4)^2 over b^2 = -1

the distance from (2,4) to (2,7) is 3, so b=3

the distance from (2,4) to your focus (2,8) is 4, so c=4

recall that in a hyperbola a^2 + b^2 = c^2, substitute to get a^2 = 7

Therefore (x-2)^2 over 7 - (y-4)^2 over 9 = -1

Nice job, reiny! Thanks for helping us out here.

## Answer This Question

## Related Questions

- algebra - a hyperbola has vertices (+-5,0) and one focus (6,0) what is the ...
- algebra - Can someone please help... a hyperbola has vertices (+-5,0) and one ...
- EASY MATH - Write the equation of a hyperbola with a center at (-5, -3), ...
- Algebra 2 - Choose the equation that best represents an ellipse for the given ...
- Hyperbolas - Find the equation of the hyperbola whose vertices are at (-1,-5) ...
- algebra - how would you solve this; Write an equation for the hyperbola with ...
- Pre-Calculus - Find the equation of the hyperbola whose vertices are at (-1,-5) ...
- Math Help PLEASE! - Find the equation of the hyperbola whose vertices are at (-1...
- Math, precalculus - Write an equation for the hyperbola with vertices (7,5),(-5,...
- math - Write an equation for the hyperbola. It's center is (0,0). Foci:(-4,0), (...

More Related Questions