Posted by
**Ali** on
.

In my bio lab we are creating serial disk dilutions (100mg, 300mg, 500mg) from a plant extraction sample.

Wood sample #1 (7mL of hexane)

Hexane 0.6651g

so .6651g of the plant was dissolved in 7mL of hexane. Then I did dilution calculations

so 0.6551g/7 mL = 0.095g/ml

so I assumed 10mL of 100mg/L

10ml x .1g/mL= 1 g

vmL x .095g/mL= 1 g

vmL= 10.52 mL

so I assumed 10mL of 300mg/mL

10ml x .3g/ml= 3g

vmL x .095g/mL= 3g

VmL= 31.57 mL

so I assumed 10mL of 500mg/mL

10 mL x .5g/mL =5 g

10mL x .095g/mL = 5g

VmL= 52.6 mL

Please let me know where I am going wrong if you a problem. I appreciate the help. Thank you.