my question is for math,
I have the problem worked out i just don't remember what the tutor who helped me told me for the explanation of steps i just like to know how they came up with that.
Directions: Solve each literal equation for the indicated variable.
A=1/2h(B+b) (for b) Area of trapezoid
A= h(B+b)/2
2A=h(B+b)
2A/h=B+b
2A/h-B=b
A=(1/2h)(B+b) (for b) Area of trapezoid
A= h(B+b)/2 is another way of writing the same thing
2A=h(B+b) Is what ou get by multiplying both sides of the equation by 2.
2A/h=B+b Is what you get by divifing both sides of the equation by h
2A/h-B=b Is what you get by subtracting B from both sides. This provides an equation for b in terms of A, h and B
I appreciate your help very much thank you this way i can do a couple of more problems similar to this one i appreciated i just couldn't remember the explanations.
To solve the given literal equation A=(1/2h)(B+b) for b, you can follow these steps:
1. Start with the equation A=(1/2h)(B+b). This is the initial equation that you need to solve for b.
2. Rewrite the equation as A= h(B+b)/2. This step involves simplifying the fraction by multiplying both sides of the equation by 2 to eliminate the denominator.
3. Multiply both sides of the equation by h to isolate the term (B+b) on the right side. This gives you the equation 2A=h(B+b).
4. Divide both sides of the equation by h to isolate the term (B+b). This step involves dividing both sides of the equation by h, resulting in the equation 2A/h=B+b.
5. Subtract B from both sides of the equation to solve for b. By subtracting B from both sides, you get the equation 2A/h-B=b, which provides an equation for b in terms of A, h, and B.
It's always helpful to understand each step of solving an equation, as it allows you to apply the same method to similar problems.