Posted by **becky** on Tuesday, January 2, 2007 at 11:44pm.

A 2000-kg car rounds a circular turn of a radius 20m. if the radius flat and the coefficient of friction between tires and road is .70, how fast can the car go without skidding?

centripetal force = frictional force

m v^2/r= mg*mu

solve for v.

um i was wondering..do i need to convert like 20m or 2000kg to anything before i do any of it?

In this case, the figures are given in SI units (meters and kilograms), so you could just work with the given figures.

But it is better to solve for v in terms of r, g and mu (the mass drops out). Then you plug in the figures including the units. So, instead of putting r = 20 and g = 9.81, you insert r = 20 m and g = 9.81 m/s^2 in your formula. Then you obtain an answer for v that automatically has units.

## Answer this Question

## Related Questions

- physics - a 2000 kg car rounds a circular turn of radius 20.0 meters. if the ...
- Physics - A 1180 kg car rounds a circular turn of radius 19.1 m. If the road is ...
- Physics - A 2050 kg car rounds a circular turn of radius 18.5 m. If the road is ...
- Physics - A car has a mass of 2500 kg rounds a circular turn with a radius of 50...
- Physics - A 1220 kg car rounds a circular turn of radius 19.2 m. If the road is ...
- Physics - A 1200-kg car rounds a corner of radius r = 45 m. If the coefficient ...
- physics - What is the maximum speed that the car can turn in a curve of radius ...
- Physics-circular force - What is the maximum speed with which a 1140 kg car can ...
- physics - what is the maximum speed with which a 1050kg car can round a turn of ...
- physics 1401!!! - A 2000-kg car rounds an unbanked curve with a radius of 45 m ...

More Related Questions